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 Posted: Fri Apr 20, 2007 4:46 pm
Here's an algebra problem I made up. I'll give 100 gold to the guild or 50 gold to the person who solves it (your choice). I'll give 10 gold to the first 5 people to post another 2-equation math problem. biggrin biggrin biggrin biggrin biggrin
Well, here it is:
3a+b=119
b+5=a
Solve for a and b
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Posted: Sat Apr 21, 2007 12:28 am
well thats a blast from the past confused
here:
a=31, b=26
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Posted: Tue Apr 24, 2007 3:26 am
I guess he really didn't like my answer...
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Posted: Tue Apr 24, 2007 4:46 pm
bluewolfcub well thats a blast from the past confused here: a=31, b=26I'm sorry. Your answer was colored white. Send me a PM telling whether you want 50 gold for yourself or 100 gold donated to the guild. biggrin biggrin biggrin
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Posted: Wed May 16, 2007 4:14 pm
...Seriously?
Well let's at least get more complicated than a system of 2 equations:
3x-14y+z=-60
x-y+2z=45
(1/2)x+y-3z=7
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Posted: Thu Jul 12, 2007 9:50 pm
I think linear problems are too easy. You can simply use determinates to solve them. I like more complicated ones...
(x + 2y)^(1/2) + sin z = 3
x + y - z/[2*pi] = 0
x^2 + y^2 = 289
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Posted: Thu Jul 19, 2007 12:42 am
*taking a probably futile attempt:*
x+y=z/2pi
2pi(x)+2pi(y)=z
sqrt(x+2y)+sin(2pi(x)+2pi(y))=3
3-sqrt(x+2y)=sin(2pi(x)+2pi(y))
...GAH, I don't know how to get rid of the sine and keep the problem looking nice. :XP:
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Posted: Sun Nov 25, 2007 2:17 pm
The right half comes to zero using the addition formula for sin.
sin(2pi(x)+2pi(y))=sin(2pi(x))cos(2pi(y))+cos(2pi(x))sin(2pi(y))
And since we know that sin is zero at every multiple of 2pi then we get 3-sqrt(x-2y)=0
So there goes the pi and the sin smile
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Posted: Fri Nov 30, 2007 1:45 pm
khuan The right half comes to zero using the addition formula for sin. sin(2pi(x)+2pi(y))=sin(2pi(x))cos(2pi(y))+cos(2pi(x))sin(2pi(y)) And since we know that sin is zero at every multiple of 2pi then we get 3-sqrt(x-2y)=0 So there goes the pi and the sin smile But...that's only if you were looking for the integer solutions to this problem. And even if you were, there's still a discrepancy left; there aren't unique x and y solving 3-sqrt(x-2y)=0, regardless of whether or not you wanted integer solutions.
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Posted: Wed Dec 12, 2007 9:26 pm
Aww... you know a simple Maple or Matlab package can solve most of these equations in less than 10 seconds. How about solving systems of differential equations. That can be fun.
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Posted: Wed Feb 13, 2008 6:43 pm
I have a question that I don't know the answer too
Take two 2s and make them equal 5, No variables, no extra numbers, any operation.
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Posted: Wed Feb 13, 2008 8:27 pm
Severus-snape-the-second I have a question that I don't know the answer too Take two 2s and make them equal 5, No variables, no extra numbers, any operation. Write the two 2's as Roman Numerals with matchsticks: || || Now move the matchsticks like this:
V
Voila... V is the Roman Numeral for 5. (Sorry that looks so tacky... I tried to make the V out of 4 slashes, but it wouldn't work)
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Posted: Thu Feb 14, 2008 7:17 am
Okay, solve this:
Prove that every even number greater than 2 can be expressed as the sum of two primes. mrgreen
*hides*
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Posted: Tue Feb 19, 2008 5:05 pm
ka0s1337the0ry Okay, solve this: Prove that every number greater than or equal to 4 can be expressed as the sum of two primes. mrgreen *hides* What about 27?
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